Class-2 Lever: Numerical Example

In a Class 2 Lever, we are given the following information:

L1 = 30 ft

L2 = 5 ft

Weight at one end of the lever is 500 lb.

We are required to calculate the following:

a. Mechanical advantage for this lever.

b. Force required necessary at the other end of the lever to lift the 500 lb weight.

Solution

a. MA = 30/5 = 6

b. To lift the weight, F2 must be equal to 500 lb weight. Therefore F2 = 500 lb. Now we need to calculate F1.

F1 = F2/MA = 500/6 = 83.4 lb.